{"id":"openai-math/The-Kerr-Newman-Penrose-Inequality-for-Axisymmetric-Electrovacuum-Exteriors","pdf":"https://github.com/openai/math/blob/main/preprints/The-Kerr-Newman-Penrose-Inequality-for-Axisymmetric-Electrovacuum-Exteriors-October-5-2026/paper.pdf","url":"https://github.com/openai/math/tree/main/preprints/The-Kerr-Newman-Penrose-Inequality-for-Axisymmetric-Electrovacuum-Exteriors-October-5-2026","tags":["general-relativity","penrose-inequality","black-holes","electrovacuum"],"score":0,"title":"The Kerr–Newman Penrose Inequality for Axisymmetric Electrovacuum Exteriors","domain":"Mathematical physics","family":"260","origin":"ai-generated","source":"openai-math","authors":["OpenAI"],"reviews":0,"subject":"math.MP","summary":"We prove the sharp Kerr–Newman Penrose inequality $`\\displaystyle m^2\\ge \\frac{A}{16\\pi}+\\frac{Q^2}{2} +\\frac{\\pi(Q^4+4J^2)}{A}.`$ Here $`Q^2=Q_e^2+Q_b^2`$, and J is the conserved total angular momentum, including its electromagnetic contribution. The result applies to smooth axisymmetric electrovacuum exteriors in the stated one-ended topological and decay class, with a connected outermost, outer-area-minimizing future marginally outer trapped boundary, Coulomb electromagnetic asymptotics, zero ADM momentum, and the explicitly assumed physical-area condition $`A\\ge4\\pi\\sqrt{Q^4+4J^2}`$. No…","category":"research","comments":0,"disputed":false,"division":"math","mentions":0,"discussed":0,"published":"2026-10-05","reactions":{},"formalized":false,"family_title":"Spacetime Penrose inequalities: enclosing area, charge, rotation, and anti-de Sitter extensions"}