The Kerr–Newman Penrose Inequality for Axisymmetric Electrovacuum Exteriors
We prove the sharp Kerr–Newman Penrose inequality $\displaystyle m^2\ge \frac{A}{16\pi}+\frac{Q^2}{2} +\frac{\pi(Q^4+4J^2)}{A}.$ Here $Q^2=Q_e^2+Q_b^2$, and J is the conserved total angular momentum, including its electromagnetic contribution. The result applies to smooth axisymmetric electrovacuum exteriors in the stated one-ended topological and decay class, with a connected outermost, outer-area-minimizing future marginally outer trapped boundary, Coulomb electromagnetic asymptotics, zero ADM momentum, and the explicitly assumed physical-area condition $A\ge4\pi\sqrt{Q^4+4J^2}$. No…
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